PermalinkSubmitted by Ryousuke Ishikawa on Tue, 02/27/2018 - 02:14
Nice to meet you. I am grateful to have studied with your wonderful teaching materials.
Recently sliders and Flash animations on the web do not seem to work well.
I tried the latest FlashPlayer with Chrome, IE and Firefox but it did not work.
What should I do?
PermalinkSubmitted by ganley0905 on Tue, 07/24/2018 - 10:32
This is a question, not a comment. Can I copy figures from one of your pages for use on a website I am building for my startup? I will acknowledge your site as the source. Thanks. J. T. Ganley
PermalinkSubmitted by TimCHEN on Wed, 12/30/2020 - 03:42
This website supplies abundant, detailed, and reliable resources for PV learning! I've studied some parts of the section "properties of sunlight". It helps me a lot in deed. Thanks!
PermalinkSubmitted by holretz on Wed, 03/02/2022 - 17:15
I live in Aasiaat, latitude 68,7 degrees north. According to the curves for calculation of solar incidence, a solararray should be tilted around 55,5 degrees. It says somewhere else on one of the pages, that one should choose tilt equal to latitude.
This is clearly not the case for my latitude, so I don't quite understand this statement....is it true for some limited range of latitudes ?
PermalinkSubmitted by Peter W on Wed, 10/26/2022 - 07:20
I believe the formula given for solar radiation on a panel with arbitrary orientation and tilt is incorrect. I think it should be:
Smodule = Sincident .cos(Ψ-θ).[cos(α)sin(β) + sin(α)Cos(β)]
Reason: On the previous page, for a module directly facing the sun, at tilt β:
Smodule = Sincident. sin(α+ β), where
sin(α+ β) = cos(α)sin(β) + sin(α)Cos(β)
For a module at orientation θ,
Smodule = Sincident .cos(Ψ-θ). sin(α+ β), so
Smodule = Sincident .cos(Ψ-θ).[cos(α)sin(β) + sin(α)Cos(β)], not as given.
Comments
how I can save this CD
how I can save this CD
There is no off line version
There is no off line version at present.
HI
HOW CAN I FIND THIS INFORMATION ON BOOKS PDF
hard copy
hello sir, im electrical engineer.I need a hard copy of whole attachments.
waiting for your kind responce.
thank you.
iPhone,iPad..
How to see the animations on iPhone and iPad ...
The animations are in flash
The animations are in flash that is not supported by the iPad. Unfortunately there are still no suitable substitutes.
Flash animations
Nice to meet you. I am grateful to have studied with your wonderful teaching materials.
Recently sliders and Flash animations on the web do not seem to work well.
I tried the latest FlashPlayer with Chrome, IE and Firefox but it did not work.
What should I do?
As far as I know they still
As far as I know they still work. Which page is the problem?
USe of Figures from your site
This is a question, not a comment. Can I copy figures from one of your pages for use on a website I am building for my startup? I will acknowledge your site as the source. Thanks. J. T. Ganley
As long as you acknowledge
As long as you acknowledge the source of the images you may use figures for your site. If it is a website just make sure you have at a minimum
Picture: www.pveducation.org
And a link to the website.
Printing Sections
I'd love to be able to print sections instead of part by part.
User's feeling: Powerful and practical website for photovoltaics
This website supplies abundant, detailed, and reliable resources for PV learning! I've studied some parts of the section "properties of sunlight". It helps me a lot in deed. Thanks!
module tilt in Aasiaat
I live in Aasiaat, latitude 68,7 degrees north. According to the curves for calculation of solar incidence, a solararray should be tilted around 55,5 degrees. It says somewhere else on one of the pages, that one should choose tilt equal to latitude.
This is clearly not the case for my latitude, so I don't quite understand this statement....is it true for some limited range of latitudes ?
S 2.4 Arbitrary Orientation and Tilt
I believe the formula given for solar radiation on a panel with arbitrary orientation and tilt is incorrect. I think it should be:
Smodule = Sincident .cos(Ψ-θ).[cos(α)sin(β) + sin(α)Cos(β)]
Reason: On the previous page, for a module directly facing the sun, at tilt β:
Smodule = Sincident. sin(α+ β), where
sin(α+ β) = cos(α)sin(β) + sin(α)Cos(β)
For a module at orientation θ,
Smodule = Sincident .cos(Ψ-θ). sin(α+ β), so
Smodule = Sincident .cos(Ψ-θ).[cos(α)sin(β) + sin(α)Cos(β)], not as given.