PermalinkSubmitted by Rahman on Sun, 06/08/2014 - 16:52
F(λ)=Φ*q*1.24/((λ(μm) *Δλ(μm)), I did not understand how this equation can be developed , here mentioned two values of λ, one is λ(μm) & another one is Δλ(μm), what does that mean , how to develop them .For the homogeneous junction how to calculate this photon flux , what could be the area & how to calculate them :)
PermalinkSubmitted by lfengsao on Wed, 03/02/2016 - 02:05
I think the first λ(μm) means to calculate the energy of the photon,and the second Δλ(μm) means to the calculation of the energy per μm in specific wave length.
Comments
Greetings :)
F(λ)=Φ*q*1.24/((λ(μm) *Δλ(μm)), I did not understand how this equation can be developed , here mentioned two values of λ, one is λ(μm) & another one is Δλ(μm), what does that mean , how to develop them .For the homogeneous junction how to calculate this photon flux , what could be the area & how to calculate them :)
The second formula
I think the first λ(μm) means to calculate the energy of the photon,and the second Δλ(μm) means to the calculation of the energy per μm in specific wave length.
i think the second Δλ(μm)
i think the second Δλ(μm) means the change in wavelength
Radiant power density,
For a given wave length, the artificial light delivers less irradiance to that of sunlight.
Why Spectral irradiance
Why Spectral irradiance increases with wavelength. The equation gives a inverse relation. Thank you.